CODEWITHSUNDEEP
pythondictionary
user3049921
user3049921

Reputation: 49

Storing averages of values in a dictionary in a separate dictionary - Python

I have a dictionary that looks like this:

scores = {'Ben': ['10', '9'], 'Alice': ['10', '10'], 'Tom': ['9', '8']}

I have calculated the average of the values for each person in the dictionary and I want to then store the averages in a separate dictionary. I would like it to look like this:

averages = {'Ben': [9.5], 'Alice': [10], 'Tom': [8.5]}

I have calculated the averages using this code:

for key, values in scores.items(): 
  avg = float(sum([int(i) for i in values])) / len(values)
  print(avg)

This gives the following output:

9.5
10.0
8.5

How can I output the averages in a separate dictionary as shown above?

Thanks in advance.

Upvotes: 1

Views: 216

Answers (4)

acushner
acushner

Reputation: 9946

you can do this with a dict comprehension in one line:

averages = {k: sum(float(i) for i in v) / len(v) for k, v in scores.items() if v}

Upvotes: 0

Kasravnd
Kasravnd

Reputation: 107297

You can use a dictionary comprehension to loop over your items and calculate the proper result:

>>> from __future__ import division
>>> scores = {'Ben': ['10', '9'], 'Alice': ['10', '10'], 'Tom': ['9', '8']}
>>> scores = {k:[sum(map(int,v))/len(v)] for k,v in scores.items()}
>>> scores
{'Ben': [9.5], 'Alice': [10.0], 'Tom': [8.5]}

Note that you need to convert your values to int that you can do it with map function map(int,v).

Upvotes: 0

Avinash Raj
Avinash Raj

Reputation: 174706

Use dict_comprehension.

>>> scores = {'Ben': ['10', '9'], 'Alice': ['10', '10'], 'Tom': ['9', '8']}
>>> {i:[float(sum(int(x) for x in scores[i]))/len(scores[i])] for i in scores}
{'Ben': [9.5], 'Alice': [10.0], 'Tom': [8.5]}

Upvotes: 0

Brionius
Brionius

Reputation: 14098

averages = {}    # Create a new empty dictionary to hold the averages
for key, values in scores.items(): 
  averages[key] = float(sum([int(i) for i in values])) / len(values)  
  # Rather than store the averages in a local variable, store them in under the appropriate key in your new dictionary.

Upvotes: 1

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