CODEWITHSUNDEEP
phpmysqlwhile-loop
three3
three3

Reputation: 2846

How to retrieve data via a while loop in PHP

I am looping through a MySQL result but I am running into an issue. The issue is that only my first if statement is being executed. The rest of my if statements are returning empty strings. What is confusing me is this: When I remove the first if statement in the while loop, the next if statement will return data but all other statements below it will not.

Here is my relevant code:

// Get Addresses
$queryAddresses  = "SELECT * FROM contact_addresses WHERE contact_id = $contactID";
$resultAddresses = mysqli_query($dbc, $queryAddresses);
$numAddresses    = mysqli_num_rows($resultAddresses);

if ($numAddresses >= 1) {
    $address_labels = '';
    $addresses      = '';
    while ($address = mysqli_fetch_array($resultAddresses, MYSQLI_ASSOC)) {
        $address_labels .= $address['label'].'<br>';

        if (!empty($address['address'])) {
            $address = $address['address'].', ';
        } else {
            $address = '';
        }
        
        /* ALL OF THE IF STATEMENTS BELOW THIS LINE RETURN EMPTY STRINGS EVEN THOUGH THE INFORMATION IS STORED IN THE DATABASE.  */
        if (!empty($address['address_two'])) {
            $address_two = $address['address_two'].', ';
        } else {
            $address_two = '';
        }

        if (!empty($address['city'])) {
            $city = $address['city'].', ';
        } else {
            $city = '';
        }

        if (!empty($address['state'])) {
            $state = $address['state'].', ';
        } else {
            $state = '';
        }

        if (!empty($address['zip'])) {
            $zip = $address['zip'].', ';
        } else {
            $zip = '';
        }

        if (!empty($address['country'])) {
            $country = $address['country'].', ';
        } else {
            $country = '';
        }

        $addresses .= $address.''.$address_two.''.$city.''.$state.''.$zip.''.$country.'<br>';
    }
}

Upvotes: 0

Views: 79

Answers (4)

Vineet Mishra
Vineet Mishra

Reputation: 100

In the following code change the variable, as it is replacing the values of the array by assigning new value.

 if (!empty($address['address'])) {
        $address = $address['address'].', ';//Chang variable name here
    } else {
        $address = '';//Chang variable name here
    }

Upvotes: 0

mahesh kalantre
mahesh kalantre

Reputation: 51

Plz paste following Code in your editor:
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "databasename";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
}

$sql = "SELECT * FROM users";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
    // output data of each row
    while($row = $result->fetch_assoc()) {
        //echo "id: " . $row["id"]. " - Name: " . $row["first_name"]. " " . $row["last_name"]. "<br>";
        $fnanem ="";
        $lnanem ="";
        if(!empty($row["first_name"])){
            $fnanem = $row["first_name"];
        }else{
            $fnanem = "";
        }

        if(!empty($row["last_name"])){
            $lnanem = $row["last_name"];
        }else{
            $lnanem = "";
        }

        echo $fnanem."---->".$lnanem."<br>";
    }
} else {
    echo "0 results";
}
$conn->close();

Upvotes: 0

itssajan
itssajan

Reputation: 830

while ($address = mysqli_fetch_array($resultAddresses, MYSQLI_ASSOC)) {
    $address_labels .= $address['label'].'<br>';

    if (!empty($address['address'])) {
        $address = $address['address'].', ';
    } else {
        $address = '';
    }
}

What I found while going through your code is you are using the same variable $address for the while loop as well as the first if statement. Try changing the loop variable, say $result and try

Upvotes: 0

Lys777
Lys777

Reputation: 456

With the line $address = $address['address'].', '; you are replacing the $address array with the new string and wiping out the array. Try changing the string variable name:

    if (!empty($address['address'])) {
        $address_one = $address['address'].', ';
    } else {
        $address_one = '';
    }

    if (!empty($address['address_two'])) {
        $address_two = $address['address_two'].', ';
    } else {
        $address_two = '';
    }

    if (!empty($address['city'])) {
        $city = $address['city'].', ';
    } else {
        $city = '';
    }

    if (!empty($address['state'])) {
        $state = $address['state'].', ';
    } else {
        $state = '';
    }

    if (!empty($address['zip'])) {
        $zip = $address['zip'].', ';
    } else {
        $zip = '';
    }

    if (!empty($address['country'])) {
        $country = $address['country'].', ';
    } else {
        $country = '';
    }

    $addresses .= $address_one.''.$address_two.''.$city.''.$state.''.$zip.''.$country.'<br>';

Upvotes: 1

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