CODEWITHSUNDEEP
pythonlinuxbashshellunix
Young
Young

Reputation: 53

IF statement : Shell to python

Lets say 

DIR2 = /tmp/test'
'dirName = stats

if [ -d /$DIR2/$dirName/* ]

Above is what I have. It checks if /tmp/test/stats directory contains any files or directories inside of it. If it does contain something then I will print out yes.

How can I translate this into python language ?

if os.path.exists(DIR2 + "/" + dirName + ):
    print "pass"

Is what I tried so far..

But I know I need one more word at the end of the if statement.

Upvotes: 0

Views: 85

Answers (2)

Etan Reisner
Etan Reisner

Reputation: 81042

I believe this does what you want without requiring creation of a list with the entire set of filenames in the directory.

hasContents = False
for (root, dirs, files) in os.walk(DIR2 + "/" + dirName):
    if dirs or files:
        hasContents = True
    break

Upvotes: 0

mgilson
mgilson

Reputation: 310187

I suppose that the easiest way is to check if the list returned by os.listdir is non-empty...

if os.listdir(os.path.join(DIR2, dirName)):
    print("Not empty!")

Upvotes: 2

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