Reputation: 103
I am using this function -
public BufferedReader GetResponse(String url, String urlParameters){
HttpsURLConnection con=null;
try{
URL obj = new URL(url);
con = (HttpsURLConnection) obj.openConnection();
//add reuqest header
con.setRequestMethod("POST");
// Send post request
con.setDoOutput(true);
DataOutputStream wr = new DataOutputStream(con.getOutputStream());
wr.writeBytes(urlParameters);
wr.flush();
wr.close();
int responseCode = con.getResponseCode();
BufferedReader returnValue= new BufferedReader(new InputStreamReader(con.getInputStream()));
con.disconnect();
return returnValue;
}
catch(Exception e){
System.out.println("--------------------There is an error in response function ");
e.printStackTrace();
LOGGER.error("There is an arror in AjaxCAll function of login controller."+e.getMessage());
LOGGER.debug("There is an arror in AjaxCAll function of login controller.");
return null;
}
finally{
}
}
If I am using this -
con.disconnect();
Then I am getting java.io.IOException: stream is closed error, But if I comment the con.disconnect() line then everything is working fine. I don't know why this is happening.
Calling function
BufferedReader rd = utilities.GetResponse(url, urlParameters);
// Send post request
String line = "";
try{
while ((line = rd.readLine()) != null) { //getting error here if i close connection in response method
// Parse our JSON response
responsString += line;
JSONParser j = new JSONParser();
JSONObject o = (JSONObject) j.parse(line);
if (o.containsKey("response")) {
restMessage = (Map) o.get("response");
} else {
restMessage = (Map) o;
}
}
} finally{
rd.close();
}
Upvotes: 2
Views: 5518
Reputation: 1213
From JavaDoc of HttpURLConnection
(which HttpsURLConnection extends):
Calling the disconnect() method may close the underlying socket if a persistent connection is otherwise idle at that time.
Inside your GetResponse()
method, you got a reference to the HttpsURLConnection
's InputStream
as a BufferedReader
. However, when you used con.disconnect()
, you closed that underlying InputStream
.
In the code that calls the GetResponse()
method, you when you later try to use the returned BufferedReader
, you get an the java.io.IOException: stream is closed error
because you have already indirectly closed that stream with con.disconnect()
.
You need to rearrange your code to not call con.disconnect()
until you are finished with your BufferedReader
.
This is one approach:
GetResponse():
public HttpsURLConnection GetResponse(String url, String urlParameters) {
HttpsURLConnection con = null;
DataOutputStream wr = null;
try{
URL obj = new URL(url);
con = (HttpsURLConnection) obj.openConnection();
//add request header
con.setRequestMethod("POST");
// Send post request
con.setDoOutput(true);
wr = new DataOutputStream(con.getOutputStream());
wr.writeBytes(urlParameters);
wr.flush();
}
catch(Exception e) { //better to catch more specific than Exception
System.out.println("--------------------There is an error in response function ");
e.printStackTrace();
LOGGER.error("There is an arror in AjaxCAll function of login controller."+e.getMessage());
LOGGER.debug("There is an arror in AjaxCAll function of login controller.");
return null;
}
finally{
if(wr != null) {
wr.close();
}
}
return con;
}
Calling code:
HttpsURLConnection con = utilities.GetResponse(url, urlParameters);
if(con == null) {
//stop processing or maybe throw an exception depending on what you want to do.
}
BufferedReader rd = null;
// Send post request
String line = "";
try{
int responseCode = con.getResponseCode(); //what's this for? nothing is being done with the variable
rd = new BufferedReader(new InputStreamReader(con.getInputStream()));
while ((line = rd.readLine()) != null) {
// Parse our JSON response
responsString += line;
JSONParser j = new JSONParser();
JSONObject o = (JSONObject) j.parse(line);
if (o.containsKey("response")) {
restMessage = (Map) o.get("response");
}
else {
restMessage = (Map) o;
}
}
}
catch(Exception e) { //better to catch more specific than Exception
//handle exception
}
finally {
if(rd != null) {
rd.close();
}
con.disconnect(); //we already checked if null above
}
Upvotes: 2