CODEWITHSUNDEEP
pythonregexstringpython-3.x
Croll
Croll

Reputation: 3791

How to extract number from end of the string

I have a string like "Titile Something/17". I need to cut out "/NNN" part which can be 3, 2, 1 digit number or may not be present.

How you do this in python? Thanks.

Upvotes: 4

Views: 4953

Answers (4)

lunaferie
lunaferie

Reputation: 401

data = "Titile Something/17"

print data.split("/")[0]
'Titile Something' 
print data.split("/")[-1] #last part string after separator /
'17'

or

print data.split("/")[1] # next part after separator in this case this is the same
'17'

when You want add this to the list use strip() to remove newline "\n"

print data.split("/")[-1].strip()
'17'

~

Upvotes: 2

thefourtheye
thefourtheye

Reputation: 239473

You don't need RegEx here, simply use the built-in str.rindex function and slicing, like this

>>> data = "Titile Something/17"
>>> data[:data.rindex("/")]
'Titile Something'
>>> data[data.rindex("/") + 1:]
'17'

Or you can use str.rpartition, like this

>>> data.rpartition('/')[0]
'Titile Something'
>>> data.rpartition('/')[2]
'17'
>>>

Note: This will get any string after the last /. Use it with caution.

If you want to make sure that the split string is actually full of numbers, you can use str.isdigit function, like this

>>> data[data.rindex("/") + 1:].isdigit()
True
>>> data.rpartition('/')[2].isdigit()
True

Upvotes: 4

vks
vks

Reputation: 67968

I need to cut out "/NNN"

x = "Titile Something/17"
print re.sub(r"/.*$","",x)   #cuts the part after /
print re.sub(r"^.*?/","",x)  #cuts the part before /

Using re.sub you can what you want.

Upvotes: 1

Avinash Raj
Avinash Raj

Reputation: 174706

\d{0,3} matches from zero upto three digits. $ asserts that we are at the end of a line.

re.search(r'/\d{0,3}$', st).group()

Example:

>>> re.search(r'/\d{0,3}$', 'Titile Something/17').group()
'/17'
>>> re.search(r'/\d{0,3}$', 'Titile Something/1').group()
'/1'

Upvotes: 3

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