Reputation: 3718
I want to post my MVC form with jquery . My view model is this
public class DemoViewModel
{
[Required]
public string FirstName { get; set; }
[Required]
public string LastName { get; set; }
}
and my controller is
[HttpPost]
public JsonResult LongRunningDemoProcess(DemoViewModel model)
{
Thread.Sleep(1000);
return Json(model, "json");
}
and my view has the following code
@model WebApplication2.Models.DemoViewModel
@{
ViewBag.Title = "Home Page";
}
@using (Html.BeginForm("LongRunningDemoProcess", "Home", FormMethod.Post,
new { encType = "multipart/form-data", id = "myform", name = "myform" }))
{
<div class="form-group">
@Html.LabelFor(model => model.FirstName,
new { @class = "control-label col-md-2" })
<div class="col-md-10">
@Html.EditorFor(model => model.FirstName)
@Html.ValidationMessageFor(model => model.FirstName)
</div>
</div>
<div class="form-group">
@Html.LabelFor(model => model.LastName,
new { @class = "control-label col-md-2" })
<div class="col-md-10">
@Html.EditorFor(model => model.LastName)
@Html.ValidationMessageFor(model => model.LastName)
</div>
</div>
<input type="submit" name="operation" id="process" value="process" />
}
<div id="divProcessing">
<p>Processing, please wait . . . <img src="../../Content/ajax-loader.gif"></p>
</div>
<div id="divResult">
</div>
@section Scripts {
@Scripts.Render("~/bundles/jqueryval")
<script type="text/javascript">
$(document).ready(function () {
// Hide the "busy" Gif at load:
$("#divProcessing").hide();
// Handle the form submit event, and make the Ajax request:
$("#myform").on("submit", function (event) {
event.preventDefault();
// Show the "busy" Gif:
$("#divProcessing").show();
var url = $(this).attr("action");
var formData = $(this).serialize();
$.ajax({
url: url,
type: "POST",
data: formData,
dataType: "json",
success: function (resp) {
// Hide the "busy" gif:
$("#divProcessing").hide();
// Do something useful with the data:
$("<h3>" + resp.FirstName + " " + resp.LastName + "</h3>").appendTo("#divResult");
}
})
});
});
</script>
}
but the problem is that even if their are errors of required field the form is posted and get the result
I tried to test this code if($("#myform").valid())
but there is no method available .
How can I test the validation by using jquery.validate.js as it is included already.
Thanks
Upvotes: 2
Views: 15772
Reputation: 3718
I have solved it by including jquery.validate.unobtrusive.js in my bundles
bundles.Add(new ScriptBundle("~/bundles/jqueryval").Include(
"~/Scripts/jquery.validate*",
"~/Scripts/jquery.validate.unobtrusive.js"
));
and check like this
if (!$("#myform").valid()) {
alert('not valid');
}
else{
// ajax logic
}
Upvotes: 6
Reputation: 33305
Due to submitting the form via ajax you will have to manually call it.
This is one approach you could take:
$.validator.unobtrusive.parse($form);
$form.validate();
if ($form.valid()) {
// ajax call
}
else {
// Failed show errors
}
If it fails the errors are contained within $form.validate().errorList
but you have to manually parse them.
You can do this as follows:
$.each($form.validate().errorList, function (key, value) {
$errorSpan = $("span[data-valmsg-for='" + value.element.id + "']");
$errorSpan.html("<span style='color:red'>" + value.message + "</span>");
$errorSpan.show();
});
This simply replaces your validation for messages manually.
Upvotes: 8