CODEWITHSUNDEEP
c++printfcouttrigonometry
Alok
Alok

Reputation: 93

Getting different output for cout and printf while printing same variable

Using Devc++ for printf getting 0.00000 and for cout getting some weird output.

#include<iostream>
#include<cmath>
#include<stdio.h>
using namespace std;
main()
{
   float i,j=M_PI;
   i=sin(j);
   printf("%f \n",i);
   cout<<i;
}

Upvotes: 0

Views: 388

Answers (2)

Eric Fortin
Eric Fortin

Reputation: 7603

As mentioned you get different output values because the cout one uses scientific notation and the printf defaults to 6 decimal places. If you increase it by using

printf("%.013f \n",i);

You'll get the same value.

Now not all decimal numbers can be represented with floating point representation which is why you don't get the result you are expecting.

Also here's a question on how sin might be implemented on different platform, you can then see why sine of PI might not be 0.

Upvotes: 2

Mark B
Mark B

Reputation: 96251

It looks to me like M_PI isn't exactly pi (we know it can't be), and the result from sin isn't exactly zero.

printf with %f represents output numbers rounded as a "normal" decimal while cout uses an adaptive format (roughly %g in printf as I recall) that uses scientific notation to represent the small number.

Also note that %f means double but that the varargs helpfully promotes your float to a double when being passed in.

Upvotes: 2

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