Reputation: 409
I'm interested in finding the row before the max value in R. The dataframe looks like this:
timeround n
1 01:00 11
2 02:00 6
3 03:00 4
4 04:00 4
5 05:00 7
6 06:00 22
7 07:00 63
8 08:00 142
9 09:00 155
10 10:00 220
11 11:00 143
12 12:00 98
13 13:00 111
14 14:00 115
15 15:00 129
16 16:00 128
17 17:00 102
18 18:00 90
19 19:00 108
20 20:00 92
21 21:00 90
22 22:00 102
23 23:00 44
24 24:00 20
Currently I'm able to show the max value, using:
with(tweetcount, timeround[n== max(n)])
giving me the value "10:00"
How do I compute R to give me the value before the max value - in this case "9:00"?
Upvotes: 3
Views: 567
Reputation: 887118
You could use which
with(tweetcount, timeround[which(n== max(n))-1])
If there is only a single max
value
tweetcount$timeround[which.max(tweetcount$n)-1]
Upvotes: 2