CODEWITHSUNDEEP
luastring.formatlua-5.3
Sleepwom
Sleepwom

Reputation: 227

How to print lld in Lua 5.3

string.format (formatstring, ···)

Returns a formatted version of its variable number of arguments following the description given in its first argument (which must be a string). The format string follows the same rules as the ISO C function sprintf. The only differences are that the options/modifiers *, h, L, l, n, and p are not supported and that there is an extra option, q.

Lua 5.3 doesn't support lld, how can I print lld in Lua 5.3?

Upvotes: 3

Views: 2854

Answers (1)

Yu Hao
Yu Hao

Reputation: 122383

Short answer: use %d.

In C sprintf, %lld is used to format a long long type, which is an integer type at least 64 bit.

In Lua 5.3, the type number has two internal representations, integer and float. Integer representation is 64-bit in standard Lua. You can use %d to print it no matter its internal representation:

print(string.format("%d", 2^62))

Output: 4611686018427387904

In Lua source file luaconf.h, you can see that Lua converts %d to the approapriate format:

#define LUA_INTEGER_FMT     "%" LUA_INTEGER_FRMLEN "d"

and LUA_INTEGER_FRMLEN is defined as "", "l" or "ll" if different internal representation for integer is used:

#if defined(LLONG_MAX)      /* { */
/* use ISO C99 stuff */
#define LUA_INTEGER     long long
#define LUA_INTEGER_FRMLEN  "ll"
//...

Upvotes: 3

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