Json deserializer

Question

im currently making my first steep with json and well im complety confused. I found many examples how to deserialize json files but nothing helps me.

{
   "102": {
      "id": 102,
      "name": "cvmember3",
      "profileIconId": 28,
      "revisionDate": 1373593599000,
      "summonerLevel": 1
   },
   "101": {
      "id": 101,
      "name": "IS1ec76a704e9b52",
      "profileIconId": -1,
      "revisionDate": 1355466175000,
      "summonerLevel": 1
   }

}

This is the json i object i got, the problem is im to stupid to deseralize it. What i tried till now:

            String name= (string) new JavaScriptSerializer().Deserialize<Dictionary<String, object>>(json)["name"];

Im missing the index, and dont know how to add it anyone, can say me the correct line to deserialize, i has acces to the libary json.net

Answer 1

Alternatively you could define a class for the data you're going to get back and then parse your JSON into a dictionary something like this:

public class DataClass
{
    public int id;
    public string name;
    public int profileIconId;
    public long revisionDate;
    public int summonerLevel;
}

Then

Dictionary<int, DataClass> myDictionary = JsonConvert.DeserializeObject<Dictionary<int, DataClass>>(json);
string foundName = myDictionary[102].name;

Answer 2

If you only want one item from the string (i only need to get one arttribut), you can use NewtonSoft to fish out the item you need:

using Newtonsoft.Json.Linq;

// read from where ever
string jstr = File.ReadAllText("C:\\Temp\\101.json");

JObject js = JObject.Parse(jstr);
var data102 = js["102"]["name"];       // == "cvmember3"

var data101 = js["101"]["name"];           // == "IS1ec76a704e9b52"

Console.WriteLine("Name for 101 is '{0}'", data101.ToString());
Console.WriteLine("Name for 102 is '{0}'", data102.ToString());

Output:

Name for 101 is 'IS1ec76a704e9b52'
Name for 102 is 'cvmember3'

This is a quick way to get at just one item value but it assumes you know what it looks like and where it is stored.