CODEWITHSUNDEEP
pythonregex
Aliya
Aliya

Reputation: 31

regular expression in python for 'month year'

'\b\[a-bA-B]{4,10}\s\w{4}\b' is this the regular expression for 'may 2013' or any such format date in python?

import re
regex=re.compile('\b\[a-z]{4-10}\s\w{4}\b')
for line in text:
    list = regex.findall(line)
    for w in list:
        print w

Upvotes: 0

Views: 7501

Answers (3)

Muhammad Haseeb
Muhammad Haseeb

Reputation: 644

Extending last answer further. Regex below is able to find month in digit too.

(?P<month>([a-zA-Z]+)|(\d{2}))\s+(?P<year>\d{4})

Like these two:

  1. 02 2018
  2. july 2018

Upvotes: 0

Sede
Sede

Reputation: 61225

What about this

re.compile(r'\w{3}\s+[0-9]{4}')
  • \w{3} match any word character [a-zA-Z0-9_] three times
  • \s+ match any white space character [\r\n\t\f ]
  • [0-9]{4} match a single character present in the list below Exactly 4 times

Upvotes: 1

Alexandre
Alexandre

Reputation: 1683

The regex pattern for a date format like may 2013 is the following:

re.compile('[a-zA-Z]+\s+\d{4}')

Also, you can retrieve the month or year, by using group names, with the following code snippet:

regex = re.compile('(?P<month>[a-zA-Z]+)\s+(?P<year>\d{4})')
m = regex.search('may 2013')
print(m.group('month'), m.group('year'))

Upvotes: 4

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