Reputation: 3264
Let's suppose I have following AVL tree and my task is to find next greater element of given element (i.e. it's 7 for 6). What algorithm can I use?
Upvotes: 1
Views: 2260
Reputation: 1505
You walk recursivly through the nodes and if you found i.e. the node 6, then you return deepest left children..
pseudo code:
function find_bigger_key(key, node):
if node = null then
return null
else if node.key = key then
return min_node(node)
else if key < node.key then
return find_bigger_key(key, node.left)
else
return find_bigger_key(key, node.right)
function min_node(node):
if node.ltree = null then
return node
else
return min_node(node.ltree)
That is only a example how you could do it, but it depends how your AVLTree object model looks like.
A example implementation in python:
class AVLTree(object):
def __init__(self, key, ltree=None, rtree=None):
self.key = key ; self.ltree = ltree ; self.rtree = rtree ;
# perhaps some other attributes here....
# some other methods here ...
def find_bigger_key(self, key):
if not self: return None
elif self.key == key:
if self.rtree:
return self.rtree.min_node()
else:
return None
elif self.key > key:
return self.left.find_bigger_key(key)
else:
return self.right.find_bigger_key(key)
A example output of python:
>>> # aTree is a avltree object that represents your example
>>> key = 6
>>> found_node = aTree.find_bigger_key(key)
>>> print(found_node)
7
>>> key = 7
>>> found_node = aTree.find_bigger_key(key)
>>> print(found_node)
None
Upvotes: 2