CODEWITHSUNDEEP
javascriptundefinedtypeerror
Sam
Sam

Reputation: 255

"TypeError: undefined is not a function"

I'm learning JS on Codecademy and I'm stuck in the "switch" element part.

The instructions are: "Create your own switch statement in the editor. It can do anything you like! Make sure to include at least three cases and a default."

I always get "TypeError: undefined is not a function" I'm sure it's something dumb but I can't figure it out and I tried searching but no luck either.

And here's my code: 

// Write your code below!
var console = prompt("What's your favorite console?");
switch(console) {
    case "PS4":
        console.log("It's my favorite too!");
        break;
    case 'Xone':
        console.log("Good choice!");
        break;
    case 'Wii':
        console.log("I don't really like it.");
        break;
    default:
        console.log("That's not a current gen console!");
};

Upvotes: 0

Views: 10160

Answers (3)

GiaNU
GiaNU

Reputation: 405

You're redefining console in the first line.

console is used to, for example, print messages. The solution to your problem is to rename:

var console = ...

to a different name:

var choice = ...

Hope this helps!

Upvotes: 2

Shanqing Cai
Shanqing Cai

Reputation: 3876

"console" is an existing global variable in the JavaScript interpreter of every mainstream web browser. It basically refers to the browser "command window" that can be opened with, for example, F12 in Firefox and Chrome. If you overwrite it, as you do in your original code, you'll lose access to that important object, which is not desirable in most cases. So avoid naming your own variables "console". Other variable names to avoid are "window", "Object", etc.

Upvotes: 1

Pavel Gatnar
Pavel Gatnar

Reputation: 4053

The problem is you change the value of console. Then console.log returns the error. Rename the variable please...

Upvotes: 1

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