CODEWITHSUNDEEP
pythonsearchinput
bladexeon
bladexeon

Reputation: 706

Search for Specific raw input python

So im trying to have my script check to make sure the user input is in a correct format. for example, I'm trying to get the user to input a string that looks like:

0B/4B/07

I want to make sure the script knows that the string should look exactly like that with varying numbers and letters, but is a total len of 8 characters, and the /'s are in exactly those positions. I know there should be a way to do this with the re module but i cant seem to figure it out. Any suggestions?

Upvotes: 1

Views: 176

Answers (2)

Daniel Robertson
Daniel Robertson

Reputation: 1394

The following will test that the users input matches your format with re.search and then use re.findall to assign a tuple with each of the matches to the variable matches. [A-Za-z0-9] matches any alphanumeric character, while {2} indicates that there should be two matches of the prior character. In addition, wraping characters in () indicates that you want to return them in an re.findall.

import re

text = "0B/4B/07"

def get_input(text):
    if re.search("[A-Za-z0-9]{2}/[A-Za-z0-9]{2}/[A-Za-z0-9]{2}", text):
        matches = re.findall(
                     "([A-Za-z0-9]{2})/([A-Za-z0-9]{2})/([A-Za-z0-9]{2})",
                     text
                 )[0]
        return matches
    else:
        return None

Usage:

>>> text = "0B/4B/07"
>>> get_input(text)
('0B', '4B', '07')

Upvotes: 0

backtrack
backtrack

Reputation: 8154

    import re


    def check(word):
        pattern = "^[0-9A-Z]{2,2}/[0-9A-Z]{2,2}/[0-9A-Z]{2,2}$"

        m = re.search(pattern,word)

        if m:
         print("true")
        else :
            print("false")

#############################
    > check('0B/4B/07')   o/p true 

    >check('0B/4B/075')   o/p false

You can use regex for this

Or if len(x) == 8 and x[2] == '//' and x[5] == '//' some thing like this as suggested by @Tim Castelijns

Upvotes: 1

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