Reputation: 1272
I want to dynamically include/omit the disabled attribute on a button element. I have seen plenty of examples of dynamic attribute values, but not of attributes themselves. I have the following render function:
render: function() {
var maybeDisabled = AppStore.cartIsEmpty() ? "disabled" : "";
return <button {maybeDisabled}>Clear cart</button>
}
This throws a parse error because of the "{" character. How can I include/omit the disabled attribute based on the (boolean) result of AppStore.cartIsEmpty()?
Upvotes: 127
Views: 122914
Reputation: 1909
In case others come here for attributes other than disabled
, e.g., custom attributes like data-attr
, one can assign empty string ""
as the value in the object to be spread to eliminate the value of the attribute. With the attribute name only available on the resulted HTML.
For example:
<div {...(trueOrFalse && { [`data-attr`]: "" })}></div>
Furthermore, if you wish the name of the attribute being dynamic too. Due to template strings support string interpolation, you can put state into it to make the name of attribute dynamic.
<div {...(trueOrFalse && { [`${state}`]: "" })}></div>
Upvotes: 1
Reputation: 36408
You can pass a boolean to the disabled
attribute.
render: function() {
return <button disabled={AppStore.cartIsEmpty()}>Clear cart</button>
}
function Test() {
return (
<div>
<button disabled={false}>Clear cart</button>
<button disabled={true}>Clear cart</button>
</div>
);
}
ReactDOM.render(<Test />, document.querySelector("#test-container"));
console.log(Array.from(document.querySelectorAll("button")));
<script crossorigin src="https://unpkg.com/react@17/umd/react.development.js"></script>
<script crossorigin src="https://unpkg.com/react-dom@17/umd/react-dom.development.js"></script>
<div id="test-container"></div>
Upvotes: 57
Reputation: 21236
I'm using React 16 and this works for me (where bool
is your test):
<fieldset {...(bool && {disabled:true})}>
Basically, based on the test (bool
) you return an object with the conditional attributes or you don't.
Also, if you need to add or omit multiple attributes you can do this:
<fieldset {...(bool && {disabled:true, something:'123'})}>
For more elaborate attribute managed I suggest you prefab the object with (or without) the attributes outside of JSX.
Upvotes: 74
Reputation: 11
First you can simply check
<button disabled={true}>Button 1</button>
<button disabled={false}>Button 2</button>
Note: **disabled value is not String, it should be Boolean.
Now for dynamic. You can simply write
<button type="button" disabled={disable}
onClick={()=>this.setSelectValue('sms')} >{this.state.sms}</button>
As you can see I am using disabled property and in curly brackets it can be local variable/state var.
The variable disable
contains values true/false.
Upvotes: 0
Reputation: 61
A simple and clean way of doing it
<button {...disabled && {disabled: true}}>Clear cart</button>
disabled should come from props like this
<MyComponent disabled />
Upvotes: 6
Reputation: 459
Far cleaner than the accepted solution is the solution which AnilRedshift mentioned, but which I'll expand on.
Simply put, HTML attributes have a name and a value. As a shorthand, you can use the name only for "disabled", "multiple", etc. But the longhand version still works, and allows for React to work in it's preferred way.
disabled={disabled ? 'disabled' : undefined}
is the most legible solution.
Upvotes: 6
Reputation: 8274
The version I used was:
<button disabled={disabled ? 'disabled' : undefined}>
Click me (or dont)
</button>
Upvotes: 5
Reputation: 1052
More cleaner way of doing dynamic attributes which works for any attributes is
function dynamicAttributes(attribute, value){
var opts = {};
if(typeof value !== 'undefined' && value !== null) {
opts['"'+attribute+'"'] = value;
return opts;
}
return false;
};
Call in your react component like following
<ReactComponent {...dynamicAttributes("disabled",false)}
{...dynamicAttributes("data-url",dataURL)}
{...dynamicAttributes("data-modal",true)} />
Tips :
You could have dynamicAttributes
function in a common place/utilities and
import it to use it across all components
you could pass value as null
to not render dynamic attribute
Upvotes: 4
Reputation: 59763
The cleanest way to add optional attributes (including disabled
and others you might want to use) is currently to use JSX spread attributes:
var Hello = React.createClass({
render: function() {
var opts = {};
if (this.props.disabled) {
opts['disabled'] = 'disabled';
}
return <button {...opts}>Hello {this.props.name}</button>;
}
});
React.render((<div><Hello name="Disabled" disabled='true' />
<Hello name="Enabled" />
</div>)
, document.getElementById('container'));
By using spread attributes, you can dynamically add (or override) whatever attributes you'd like by using a javascript object instance. In my example above, the code creates a disabled
key (with a disabled
value in this case) when the disabled
property is passed to the Hello
component instance.
If you only want to use disabled
though, this answer works well.
Upvotes: 197
Reputation: 41
You can find something similar to this at the documentation.
https://facebook.github.io/react/docs/transferring-props.html
In your case could be something like this
function MyComponent(props) {
let { disabled, ...attrs } = props;
if (disabled) {
// thus, it will has the disabled attribute only if it
// is disabled
attrs = {
...attrs,
disabled: true
}
};
return (
<button {...attrs}>MyLabel</button>
)
}
This code is using ES6, but I thing you got the idea.
This is cool because you can pass many others attributes to this component and it will still work.
Upvotes: 2
Reputation: 664
This could work, problem with disabled is one could not simply set boolean for it.
if(AppStore.cartIsEmpty()){
return "<button disabled>Clear cart</button>"
}
else
{
return "<button>Clear cart</button>"
}
Upvotes: -3