CODEWITHSUNDEEP
c++ofstream
Zilinium
Zilinium

Reputation: 11

Basic use of ofstream by another function

My program is very easy, all the mess happens around the passing of the ofstream pointer as shown below.

Main programm:

int main()
{...
ofstream otf;
otf.open("hex_movie.xyz");
....
write(int (1),oc,nx,ny,otf,ck)
}

And in the write.h, it begins with

int write(int TYPE,int *oc,int nx,int ny,ofstream otf, double ck)
{.... return 0;}

I used Xcode to debug it, and it shows (only on the line of the write fucntion, sorry I cannot upload a screen shot)

Xcode/GGK/GGK/ggk.cpp:110:28: Call to implicitly-deleted copy constructor of 'ofstream' (aka 'basic_ofstream')

Can anybody help me with this, thank you very much! :)

Upvotes: 0

Views: 116

Answers (2)

axelduch
axelduch

Reputation: 10849

You are currently passing by value otf try passing it by reference

int write(int TYPE,int *oc,int nx,int ny,ofstream& otf, double ck)

Upvotes: 2

Codor
Codor

Reputation: 17605

In the signature of the function

int write(int TYPE,int *oc,int nx,int ny,ofstream otf, double ck)

the argument otf is of type ofstream, which means call by value; consequently, otf will be a copy of the agrument of the caller. You could change the signature to

int write(int TYPE,int *oc,int nx,int ny,ofstream& otf, double ck)

which will use call by reference and will use the same object as the caller.

Upvotes: 3

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