CODEWITHSUNDEEP
javagenericscovariancecontravariance
Hariharan
Hariharan

Reputation: 881

Using subtype as type parameter in class

Consider the following code snippets

    public static <T> String typeName1(Class<T extends Object> c) {
        return c.getSimpleName();
    }
    public static  String typeName2(Class<? extends Object> c) {
        return c.getSimpleName();
    }

First one is showing a compile time error, while second one compiles successfully. Why is it so?

Upvotes: 1

Views: 57

Answers (1)

Rohit Jain
Rohit Jain

Reputation: 213311

Change the first one to this:

public static <T extends Object> String typeName(Class<T> c) {
    return c.getSimpleName();
}

and it will work. That's the difference in where you put the bounds. For type parameter, you declare bounds where you declare the type parameter, and not where you use it. While for wildcards, since there is no such declaration, you give bounds as and where you use it. BTW, <T extends Object> can just be <T>.

public static <T> String typeName(Class<T> c) {
    return c.getSimpleName();
}

Upvotes: 3

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