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javaprintingintdoublemax
Hybr1d
Hybr1d

Reputation: 195

Java maximum printing doubles and ints

I have a max function that takes 5 inputs and prints the maximum depending on what the user entered. For example:

Input: 1 2 3 2.4 0.2

Output: 3 (int)

or

Input: 1.7 2 3 4.0 3.2

Output: 4.0 (double)

I can't figure out what to do. An error occurs in the second case when 4.0 == 4. How do I bypass that? 

max=(double) i;
    System.out.print(" "+i);
            if (Math.round(max) == max) {
                System.out.print(Math.round(max));
            } else {
                System.out.print(max);
            }

Upvotes: 0

Views: 52

Answers (1)

Bram
Bram

Reputation: 479

In your loop running over the string representation of the numbers, just keep both the string that was largest, and its parsed double value. Then at the end just print the string corresponding to the largest value.

    double max = -Double.MAX_VALUE;
    String smax = null;
    for (String s: args) {
        double d = Double.parseDouble(s);
        if (d > max) {
            smax = s;
            max = d;
        }
    }
    System.out.println(smax);

Upvotes: 1

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