CODEWITHSUNDEEP
linuxgccembedded-linuxpthreads
KermitG
KermitG

Reputation: 434

pthread_rwlock_init() causing a segmentation fault

I suspect I am doing something dumb here but I am getting seg faults on an embedded Linux platform (GCC compiler) when I try to run pthread_rwlock_init() on a rwlock embedded in a structure.

struct rwlock_flag {
    int flag;           // Flag
    pthread_rwlock_t * rwlock;  // Reader/writer lock for flag
};

The following causes a seg fault...

struct rwlock_flag * running;
running = (struct rwlock_flag *) malloc (sizeof(struct rwlock_flag));
rslt = pthread_rwlock_init(running->rwlock, NULL);

As does this...

pthread_rwlock_t * rwlock_dg2;
pthread_rwlock_init(rwlock_dg2,NULL);

However the following works fine...

pthread_rwlock_t rwlock_dg;
pthread_rwlock_init(& rwlock_dg,NULL);

Any thoughts?

Upvotes: 2

Views: 2797

Answers (1)

paxdiablo
paxdiablo

Reputation: 882336

Your first and second cases both try to initialise the rwlock for a pointer that points nowhere (well, technically, to a random or NULL location).

In the first case, you allocate space for your wrapper structure but not the pthread_rwlock_t* within it. Hence it would point to a random location.

This would work with an actual pthread_rwlock_t rather than a pointer to one:

struct rwlock_flag {
    int flag;                 // Flag
    pthread_rwlock_t rwlock;  // Reader/writer lock for flag
};
struct rwlock_flag * running;
running = (struct rwlock_flag *) malloc (sizeof(struct rwlock_flag));
rslt = pthread_rwlock_init(&(running->rwlock), NULL);

In the second, similarly, there's no backing storage for rwlock_dg2 so it either points to a random location (if allocated within a function) or NULL (if declared at file level). You need:

pthread_rwlock_t * rwlock_dg2 = malloc (sizeof (pthread_rwlock_t));
pthread_rwlock_init(rwlock_dg2,NULL);

Your third case, which works, does so because the pointer &rwlock_dg actually points to a real pthread_rwlock_t (which is of course rwlock_dg).

Upvotes: 9

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