CODEWITHSUNDEEP
java
ryekayo
ryekayo

Reputation: 2431

Using replaceAll() to delete after parenthesis

I am attempting to use replaceAll to delete parenthesis and commas in a numeric line of code as shown below:

00020001 OB #2 [00\01] File Meta Information Version
00020002 UI #26 [1.2.840.10008.5.1.4.1.1.4] Media Storage SOP Class UID
00020003 UI #62 [1.3.46.670589.11.0.0.11.4.2.0.8743.5.5396.2006120114483570701] Media Storage SOP
00020010 UI #20 [1.2.840.10008.1.2.1] Transfer Syntax UID

Using this line of code:

String replaced = dcmObj.toString().replaceAll("[(),*]", "");

I want to take it one step further and delete everything past the numeric code so for example:

00020010 UI #20 [1.2.840.10008.1.2.1] Transfer Syntax UID

Will be turned to just:

00020010

Can someone show me how I would do that with the line of code I am using?

Upvotes: 1

Views: 55

Answers (2)

Pshemo
Pshemo

Reputation: 124275

You can try storing number placed ad start of line in group and replace entire line with match from this group.

yourTest = yourText.replaceAll("(?m)^(\\d+).*", "$1");

(?m) represents MULTILINE flag which lets ^ match start of line, not only start of entire string.

DEMO:

String s = 
        "00020001 OB #2 [00\\01] File Meta Information Version\r\n" + 
        "00020002 UI #26 [1.2.840.10008.5.1.4.1.1.4] Media Storage SOP Class UID\r\n" + 
        "00020003 UI #62 [1.3.46.670589.11.0.0.11.4.2.0.8743.5.5396.2006120114483570701] Media Storage SOP\r\n" + 
        "00020010 UI #20 [1.2.840.10008.1.2.1] Transfer Syntax UID";
System.out.println(s.replaceAll("(?m)^(\\d+).*", "$1"));

Output:

00020001
00020002
00020003
00020010

Upvotes: 1

Zielu
Zielu

Reputation: 8562

Simply match the rest of your string after the digits.

replaceAll(" UI.*","")

However, I would recommend matching the numerical id instead, it is cleaner and more robust in case your lines format would change

id = dcmObj.toString().matches("\d+");

Upvotes: 1

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