CODEWITHSUNDEEP
java
user4696584
user4696584

Reputation:

why does system.out.write convert int value to char?

Suppose that int b = 99. Why does system.out.write(b) print "c" instead of 99? At the same time using PrintWriter I get actual value of b (99) even if b = 'c'?

Upvotes: 2

Views: 254

Answers (3)

CodeCamper
CodeCamper

Reputation: 6984

Both output 'c' exactly the same and as to be expected. System.out.write and PrintWriter.write both output the same result... 'c'

    int b = 99;
    System.out.write(b);
    System.out.flush();
    System.out.println("");
    PrintWriter x = new PrintWriter(System.out);
    x.write(b);
    x.flush();

outputs

c

c

Look at the number 99 on this chart http://www.asciitable.com/

Here is what the documentation says about the System.out.write method

Note that the byte is written as given; to write a character that will be translated according to the platform's default character encoding, use the print(char) or println(char) methods.

The PrintWriter has an overloaded method for passing a String. But in this case when you pass a number which it converts to a char.

Writes a single character. Overrides: write(...) in Writer Parameters:c int specifying a character to be written.

It appears your problem is that you are using the println method for the PrintWriter but not for System.out, just use the println method in System.out and you will get the same results. This is because you are using an overloaded constructor which accepts and prints an integer but for write the method takes the number and converts it to a char, that is just what it is for.

Upvotes: 1

S. Pauk
S. Pauk

Reputation: 5318

Suppose that int b = 99. Why does system.out.write(b) print "c"

because U0063 is "c"

and

99 = 0x63

Upvotes: 3

Darshan Lila
Darshan Lila

Reputation: 5868

The thing is System.out.write(int) would consider the argument as byte and would write it to stream.

In your case since you passed 99 which is U0063, hence c is printed.

Upvotes: 3

Related Questions