CODEWITHSUNDEEP
androidfloating-pointnumberformatexceptiontextwatcher
Kangel
Kangel

Reputation: 61

NumberFormatException on DecimalFormat Float

after many attempts I managed to create a pattern for Float , I managed to do it by return ActivityResult and set it in the corresponding field . Now I have a problem with this TextWatcher that does not accept the pattern of Float , can anyone help me out ?

This is the TextWather 

   private abstract class TextChangedListener implements TextWatcher
{

    public abstract void numberEntered(Float number);

    @Override
    public void afterTextChanged(Editable s)
    {
        String text = s.toString();
        try
        {
            Float parsedFloat = Float.valueOf(text);
            numberEntered(parsedFloat);
        } catch (NumberFormatException e)
        {
            Log.w(getPackageName(), "Non si puo' parsare '" + text + "' col numero", e);
        }
    }

    @Override
    public void beforeTextChanged(CharSequence s, int start, int count, int after)
    {
    }

    @Override
    public void onTextChanged(CharSequence s, int start, int before, int count)
    {
    }
}

This is the Float pattern

DecimalFormat dec = new DecimalFormat("###,##0.00", DecimalFormatSymbols.getInstance(Locale.ITALIAN));

Upvotes: 1

Views: 1261

Answers (3)

Rajesh Satvara
Rajesh Satvara

Reputation: 3964

It's mostly due to the Locale issue, just define locale as English your issue will be resolved.

 public double convertTwoDecimalPointAmount(double amount) {
        DecimalFormat df = new DecimalFormat("0.00", DecimalFormatSymbols.getInstance(Locale.ENGLISH));
        return Double.parseDouble(df.format(amount));
    }

Upvotes: 0

Kangel
Kangel

Reputation: 61

Thanks to all! I resolve my problem with this method!

    private void decimalFormatWithSymbol() {
    dec = new DecimalFormat("##0.00", DecimalFormatSymbols.getInstance(Locale.ITALIAN));
    dfs = new DecimalFormatSymbols();
    dfs.setDecimalSeparator('.');
    dec.setDecimalFormatSymbols(dfs);
    }

Upvotes: 1

Anggrayudi H
Anggrayudi H

Reputation: 15165

If you want to give some decimal numbers to float, convert it to double:

float f = 90;
DecimalFormat decimal2 = new DecimalFormat("#.##"); // gives 2 numbers after '.'
double dec = Double.valueOf(decimal2.format(f));

Above code will gives you the output:

90.00

Upvotes: 0

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