CODEWITHSUNDEEP
phpisset
gomesh munda
gomesh munda

Reputation: 850

!empty function giving weird value

I have a php page where i have a hidden input as follows:

<input type="hidden" id="selOption'+(i+1)+'" name="selOption'+(i+1)+'" value="0"/>

As you can see that it has default value=0. Now using Ajax i'm sending value of the above input along with some other hidden input type="hidden" to another page like:

    function showbtn(no,tid,tp){
        var v_qno = document.getElementById("QuestionID"+no).value;
        var v_secid = document.getElementById("sectionID"+no).value;
        var v_selans = 0;
            var v_vstatus = document.getElementById("visitStatus"+no).value;
            v_selans = document.getElementById("selOption"+no).value;

        var dataString = 'testId='+tid+'&secId='+v_secid+'&qNo='+ v_qno+'&selAns='+v_selans+'&vStat='+v_vstatus;
        alert(dataString);
        $.ajax({
            type: "POST",
            url: "../member/updtBttnStatus.php",
            data: dataString,
            cache: false,
            success: function(result){
                 //some code
                }
                alert(result);
            }
        });
    }

My problem is that in the updtBttnStatus.php page when i am using 

if (!empty($_POST['selAns'])){
//some code here}
else{//}

to validate the value it goes to else part of the if loop whereas it should not be so because default value=0 being set in the first page.

Please help me as to what is that i am missing. Thanks in advance

Upvotes: 0

Views: 57

Answers (1)

Kevin
Kevin

Reputation: 41885

No, you shouldn't use empty() on a 0. You'll get a false positive because in your case 0 is a valid value.

Quoting the manual:

The following things are considered to be empty:

"" (an empty string)
0 (0 as an integer)
0.0 (0 as a float)
"0" (0 as a string)
NULL
FALSE
array() (an empty array)
$var; (a variable declared, but without a value)

As an alternative, use isset() in your if block instead:

if(isset($_POST['selAns']) && $_POST['selAns'] !== '') {
    echo 'hi';
}

Upvotes: 3

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