CODEWITHSUNDEEP
stringshellsh
apr
apr

Reputation: 696

Comparison of a string variable and a string is throwing error in shell script

I am working on a small shell script for backing up the sever logs to amazone. We have multiple servers running on production. So I wrote a script that dynamically detect the server and do the back up. But I am facing an issue while comparing two strings. I will give the code snippet below I wrote and the error.

test.sh    

host="$(hostname)"
if [ "$host" == "server1-myapp.com" ]; then
   function_1 $host
elif [ "$host" == "server2-myapp.com" ]; then
   function_2 $host
elif [ "$host" == "server3-myapp.com" ]; then
   function_3 $host
fi

function_1 () {
   echo "host name is $1"
}

function_2 () {
   echo "host name is $1"
}

function_3 () {
   echo "host name is $1"
}

But when running test.sh as sh test.sh I am getting the following error.

 test.sh: 2: [: server1-myapp.com: unexpected operator
 test.sh: 4: [: server1-myapp.com: unexpected operator
 test.sh: 6: [: server1-myapp.com: unexpected operator

I tried different ways to match two strings as one is a variable and other is a inline string, it is not matching strings properly can any one please help me, I am kind off stuck.

Upvotes: 0

Views: 113

Answers (1)

Sylvain Bugat
Sylvain Bugat

Reputation: 8164

To compare string in shell with the [ ] operator it's with = and not ==. This will works:

if [ "$host" = "server1-myapp.com" ]; then

Upvotes: 1

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