Reputation: 709
how can i get the folder names existing in a directory using Python ?
I want to save all the subfolders into a list to work with the names after that but i dont know how to read the subfolder names ?
Thanks for you help
Upvotes: 47
Views: 93898
Reputation: 925
For python 3 I'm using this script
import os
root='./'
dirlist = [ item for item in os.listdir(root) if os.path.isdir(os.path.join(root, item)) ]
for dir in dirlist:
print(dir)
Upvotes: 5
Reputation: 337
Python 3.x: If you want only the directories in a given directory, try:
import os
search_path = '.' # set your path here.
root, dirs, files = next(os.walk(search_path), ([],[],[]))
print(dirs)
The above example will print out a list of the directories in the current directory like this:
['dir1', 'dir2', 'dir3']
The output contains only the sub-directory names.
If the directory does not have sub-directories, it will print:
[]
os.walk() is a generator method, so use next() to only call it once. The 3-tuple of empty strings is for the error condition when the directory does not contain any sub-directories because the os.walk() generator returns 3-tuples for each layer in the directory tree. Without those, if the directory is empty, next() will raise a StopIteration exception.
For a more compact version:
dirs = next(os.walk(search_path), ([],[],[]))[1]
Upvotes: 1
Reputation: 1642
I use os.listdir
Get all folder names of a directory
folder_names = []
for entry_name in os.listdir(MYDIR):
entry_path = os.path.join(MYDIR, entry_name)
if os.path.isdir(entry_path):
folder_names.append(entry_name)
Get all folder paths of a directory
folder_paths = []
for entry_name in os.listdir(MYDIR):
entry_path = os.path.join(MYDIR, entry_name)
if os.path.isdir(entry_path):
folder_paths.append(entry_path)
Get all file names of a directory
file_names = []
for file_name in os.listdir(MYDIR):
file_path = os.path.join(MYDIR, file_name)
if os.path.isfile(file_path):
file_names.append(file_name)
Get all file paths of a directory
file_paths = []
for file_name in os.listdir(MYDIR):
file_path = os.path.join(MYDIR, file_name)
if os.path.isfile(file_path):
file_paths.append(file_path)
Upvotes: 6
Reputation: 531
You should import os first.
import os
files=[]
files = [f for f in sorted(os.listdir(FileDirectoryPath))]
This would give you list with all files in the FileDirectoryPath sorted.
Upvotes: 9
Reputation: 968
You can use os.walk()
# !/usr/bin/python
import os
directory_list = list()
for root, dirs, files in os.walk("/path/to/your/dir", topdown=False):
for name in dirs:
directory_list.append(os.path.join(root, name))
print directory_list
EDIT
If you only want the first level and not actually "walk" through the subdirectories, it is even less code:
import os
root, dirs, files = os.walk("/path/to/your/dir").next()
print dirs
This is not really what os.walk
is made for. If you really only want one level of subdirectories, you can also use os.listdir()
like Yannik Ammann suggested:
root='/path/to/my/dir'
dirlist = [ item for item in os.listdir(root) if os.path.isdir(os.path.join(root, item)) ]
print dirlist
Upvotes: 58
Reputation: 1573
You can use os.listdir()
here a link to the docs
Warning returns files and directories
example:
import os
path = 'pyth/to/dir/'
dir_list = os.listdir(path)
update: you need to check if the returned names are directories or files
import os
path = 'pyth/to/dir/'
# list of all content in a directory, filtered so only directories are returned
dir_list = [directory for directory in os.listdir(path) if os.path.isdir(path+directory)]
Upvotes: 12
Reputation: 387547
Starting with Python 3.4, you can also use the new pathlib
module:
from pathlib import Path
p = Path('some/folder')
subdirectories = [x for x in p.iterdir() if x.is_dir()]
print(subdirectories)
Upvotes: 17
Reputation: 691
Use os.walk(path)
import os
path = 'C:\\'
for root, directories, files in os.walk(path):
for directory in directories:
print os.path.join(root, directory)
Upvotes: 3