Reputation: 11
I have a list like this:
list=[0.2, 0.3, 0.5, 0.1, 0.7, 0.9]
I want to combine as next:
[[0.2,0.3][0.2,0.5][0.2,0.1][0.2,0.7]
[0.2,0.9][0.3,0.5][0.3,0.1][0.3,0.7]
[0.3,0.9][0.5,0.1][0.5,0.7][0.5,0.9]
[0.1,0.7][0.1,0.9][0.7][0.9]]
But i want reach this list:
[[0.2 0.3, 0.5 ][0.2 0.3 0.5, 0.1]...[0.2 0.3 0.5 0.1 0.7, 0.9]]
My code:
listOne=[0.2, 0.3, 0.5, 0.1, 0.7, 0.9]
listTwo=[]
i=0; j=0; aux=0;
while i<len(listOne):
while j<len(listOne):
print listOne[j]
listTwo.append(listOne[i])
listTwo.append(listOne[j])
j+=1
i+=1
print listTwo
This is my output list
[0.2, 0.2, 0.2, 0.3, 0.2, 0.5, 0.2, 0.1 ]
Upvotes: 0
Views: 129
Reputation: 5508
I don't really understand what you really want to do, but I guess, you want to find the possible subset of the list.
So you can use the powerset from the itertools: https://docs.python.org/2/library/itertools.html
def powerset(s):
'''powerset([1,2,3]) --> () (1,) (2,) (3,) (1,2) (1,3)(2,3) (1,2,3)'''
subset = itertools.chain.from_iterable(itertools.combinations(s, r) for r in range(len(s) + 1))
return [list(x) for x in subset]
myList = [0.2, 0.3, 0.5, 0.1, 0.7, 0.9]
subsets = powerset(myList)
If you just want to keep all the subsets with length bigger than 3, you can delete the elements with subset.remove()
, or you can use the filter() function:
subsets = filter(lambda x: len(x)>=3, subsets)
So you will get the result what you want.
Upvotes: 0
Reputation: 20339
You can use itertools.combinations
here. I didnt understand what you are expecting.
from itertools import combinations
res = [i for i in combinations(list,2)] #please dont provide variable name as list
>>>res
[(0.2, 0.3),
(0.2, 0.5),
(0.2, 0.1),
... ]
Upvotes: 1
Reputation: 18446
You can accomplish that by using a list comprehension:
listOne = [0.2, 0.3, 0.5, 0.1, 0.7, 0.9]
listTwo = [listOne[:upto] for upto in range(3, len(listOne) + 1)]
print listTwo
Output:
[[0.2, 0.3, 0.5], [0.2, 0.3, 0.5, 0.1], [0.2, 0.3, 0.5, 0.1, 0.7], [0.2, 0.3, 0.5, 0.1, 0.7, 0.9]]
Upvotes: 0