CODEWITHSUNDEEP
javascriptarraysunderscore.jslodash
diplosaurus
diplosaurus

Reputation: 2588

Omit array of keys with Underscore

Using Underscore (technically Lodash). Have an object that looks like the following.

var myObj = {
    first: {name: 'John', occupation: 'Welder', age: 30},
    second: {name: 'Tim', occupation: 'A/C Repair', kids: true},
    third: {name: 'Dave', occupation: 'Electrician', age: 32},
    fourth: {name: 'Matt', occupation: 'Plumber', age: 41, kids: false}
};

I also have a hash of arrays that I want to "clean" out of each object:

var excludes = {
    first: ['name', 'age'],
    second: ['occupation'],
    fourth: ['kids]
};

The idea is that each of the elements in the array will be dropped from the object that has the matching key. Meaning my data will end up like this:

{
    first: {occupation: 'Welder'},
    second: {name: 'Tim', kids: true},
    third: {name: 'Dave', occupation: 'Electrician', age: 32},
    fourth: {name: 'Matt', occupation: 'Plumber', age: 41}
};

I was originally trying:

_.map(myObj, function(obj, k) {
    if(_.has(excludes, k) {
        // not sure what here
    }
});

I was thinking of using omit at the innermost level, but I can only drop one key at a time, not a list of keys.

Upvotes: 1

Views: 1909

Answers (1)

georg
georg

Reputation: 214959

Actually, _.omit can take a list of keys:

result = _.transform(myObj, function(result, val, key) {
    result[key] = _.omit(val, excludes[key]);
});

Upvotes: 5

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