Reputation: 19
Given a set of numbers S.
Find maximum sum such that
Sum(A1) = Sum(A2)
Where, A1⊂S and A2⊂S and A1⋂A2=∅
And Sum(X), is the sum of all elements within the set X.
Brute Force
The easiest approach is:
print maximumSum(0,0,0)
def maximumSum(index,sum1,sum2):
ans=0
if sum1 == sum2:
ans=sum1
if index >= len(S):
return ans
m1=maximumSum(index+1,sum1+S[index],sum2)
m2=maximumSum(index+1,sum1,sum2+S[index])
m3=maximumSum(index+1,sum1,sum2)
return max(m,m1,m2,m3)
Time Complexity:O(2N)
Space Complexity:O(1)
Is there a better approach than this?
Optional:
I would like to know whether the given problem is an NP-Complete problem or not.
Edit:
1 <= Sum(S) <= 1000000
2 <= len(S) <= 100
Time Limit: 60sec(can vary depending upon language used)
Upvotes: 1
Views: 1021
Reputation: 4084
Yes It is NPC problem Partition Problem
You can see the pseudo polynomial algorithm part if the sum of the set is small
Upvotes: 1