Reputation: 4770
In my application I need to get the hour and minute separately:
NSString *currentHour=[string1 substringWithRange: NSMakeRange(0,2)];
int currentHourInNumber=[currentHour intValue];
Consider string1
contains 11:59:13 AM
which is coming from datepicker.
Here if I use above code, it's okay to get hour if it's greater than 9. Else I need to change NSMakeRange(0,1)
to get hour between 1 to 9.
Are there any methods to get the hour, minutes, etc?
Please provide me sample code.
Upvotes: 117
Views: 133076
Reputation: 1
Here's an extension on NSDate
@interface NSDate (KTelDateUtility)
-(NSUInteger)dateYear;
-(NSUInteger)dateMonth;
-(NSUInteger)dateDay;
-(NSUInteger)dateHours;
-(NSUInteger)dateMins;
-(NSUInteger)dateSeconds;
@end
@implementation NSDate (KTelDateUtility)
-(NSDateComponents*)dateCalenderComponents {
NSDateComponents* dateComponents = [[NSCalendar currentCalendar] components:NSCalendarUnitDay | NSCalendarUnitMonth | NSCalendarUnitYear fromDate:self];
return dateComponents;
}
-(NSDateComponents*)dateTimeComponents {
NSDateComponents* timeComponents = [[NSCalendar currentCalendar] components:NSCalendarUnitHour | NSCalendarUnitMinute | NSCalendarUnitSecond fromDate:self];
return timeComponents;
}
-(NSUInteger)dateYear {
return [[self dateCalenderComponents] year];
}
-(NSUInteger)dateMonth {
return [[self dateCalenderComponents] month];
}
-(NSUInteger)dateDay {
return [[self dateCalenderComponents] day];
}
-(NSUInteger)dateHours {
return [[self dateTimeComponents] hour];
}
-(NSUInteger)dateMins {
return [[self dateTimeComponents] minute];
}
-(NSUInteger)dateSeconds {
return [[self dateTimeComponents] second];
}
@end
Upvotes: 0
Reputation: 19789
NSDateComponents
All you need can be found here:
https://developer.apple.com/library/content/documentation/Cocoa/Conceptual/DatesAndTimes/Articles/dtCalendars.html
Upvotes: 6
Reputation: 15635
Use an NSDateFormatter to convert string1
into an NSDate
, then get the required NSDateComponents:
Obj-C:
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"<your date format goes here"];
NSDate *date = [dateFormatter dateFromString:string1];
NSCalendar *calendar = [NSCalendar currentCalendar];
NSDateComponents *components = [calendar components:(NSCalendarUnitHour | NSCalendarUnitMinute) fromDate:date];
NSInteger hour = [components hour];
NSInteger minute = [components minute];
Swift 1 and 2:
let dateFormatter = NSDateFormatter()
dateFormatter.dateFormat = "Your date Format"
let date = dateFormatter.dateFromString(string1)
let calendar = NSCalendar.currentCalendar()
let comp = calendar.components([.Hour, .Minute], fromDate: date)
let hour = comp.hour
let minute = comp.minute
Swift 3:
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "Your date Format"
let date = dateFormatter.date(from: string1)
let calendar = Calendar.current
let comp = calendar.dateComponents([.hour, .minute], from: date)
let hour = comp.hour
let minute = comp.minute
More about the dateformat is on the official unicode site
Upvotes: 267
Reputation: 2119
If you only need it for presenting as a string the following code is much easier
NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:@"HH:mm"];
NSString *startTimeString = [formatter stringFromDate:startTimePicker.date];
Upvotes: 53
Reputation: 1436
Swift 2.0
You can do following thing to get hours and minute from a date :
let dateFromat = NSDateFormatter()
dateFromat.dateFormat = "hh:mm a"
let date = dateFromat.dateFromString(string1) // In your case its string1
print(date) // you will get - 11:59 AM
Upvotes: 3
Reputation: 2612
This seems to me to be what the question is after, no need for formatters:
NSDate *date = [NSDate date];
NSCalendar *calendar = [NSCalendar currentCalendar];
NSDateComponents *components = [calendar components:(NSCalendarUnitHour | NSCalendarUnitMinute) fromDate:date];
NSInteger hour = [components hour];
NSInteger minute = [components minute];
Upvotes: 45
Reputation: 1365
With iOS 8, Apple introduced a helper method to retrieve the hour
, minute
, second
and nanosecond
from an NSDate object.
Objective-C
NSDate *date = [NSDate currentDate];
NSInteger hour = 0;
NSInteger minute = 0;
NSCalendar *currentCalendar = [NSCalendar currentCalendar];
[currentCalendar getHour:&hour minute:&minute second:NULL nanosecond:NULL fromDate:date];
NSLog(@"the hour is %ld and minute is %ld", (long)hour, (long)minute);
Swift
let date = NSDate()
var hour = 0
var minute = 0
let calendar = NSCalendar.currentCalendar()
if #available(iOS 8.0, *) {
calendar.getHour(&hour, minute: &minute, second: nil, nanosecond: nil, fromDate: date)
print("the hour is \(hour) and minute is \(minute)")
}
Upvotes: 4
Reputation: 6417
Swift 2.0
let dateNow = NSDate()
let calendar = NSCalendar.currentCalendar()
let hour = calendar.component(NSCalendarUnit.Hour, fromDate: dateNow)
let minute = calendar.component(NSCalendarUnit.Minute, fromDate: dateNow)
print(String(hour))
print(String(minute))
Please do take note of the cast to String in the print statement, you can easily assign that value to variables, like this:
var hoursString = String(hour)
var minutesString = String(minute)
Then you can concatenate values like this:
var compoundString = "\(hour):\(minute)"
print(compoundString)
Upvotes: 2
Reputation: 5906
If you were to use the C library then this could be done:
time_t t;
struct tm * timeinfo;
time (&t);
timeinfo = localtime (&t);
NSLog(@"Hour: %d Minutes: %d", timeinfo->tm_hour, timeinfo->tm_min);
And using Swift:
var t = time_t()
time(&t)
let x = localtime(&t)
println("Hour: \(x.memory.tm_hour) Minutes: \(x.memory.tm_min)")
For further guidance see: http://www.cplusplus.com/reference/ctime/localtime/
Upvotes: 4