CODEWITHSUNDEEP
bashshellunix
David
David

Reputation: 3105

Shell get specific words in a line

I have a file

     tadjag:x:60697:100:Name Surname IF-3/4 2015-02-02:/export/home/tadjag:/bin/bash
        linbul:x:60698:100:Name2 Surname2 IF-3/4 2015-02-02:/export/home/linbul:/bin/bash
        sarvis:x:60699:100:Name3 Surname3 IF-3/2 2015-02-02:/export/home/sarvis:/bin/bash
        deigru:x:60701:100:Name4 Surname4 IF-3/4 2015-02-02:/export/home/deigru:/bin/bash
        tauilc:x:60702:100:Name5 Surname5 IF-3/3 2015-02-02:/export/home/tauilc:/bin/bash
    ...
    ...
    ...
    ...

and I want to take only Name's and Surname's if they are from IF-3/4. So my result should be

Name Surname
Name2 Surname2
Name4 Surname4

what I done

awk -F: '{print $5}' myFile

So my output is

Name Surname IF-3/4 2015-02-02
...
...

So is it possible to get only Name's and Surname's if they are from IF-3/4

Upvotes: 0

Views: 85

Answers (2)

Claes Wikner
Claes Wikner

Reputation: 1517

awk -F'[: ]' 'NR<2||!(NR%2){print $5,$6}' file

Name Surname
Name2 Surname2
Name4 Surname4

Upvotes: 0

Avinash Raj
Avinash Raj

Reputation: 174696

Use awk's split function to split on spaces which exists on the column 5 and again it stores the splitted values to an associate array a. So a[1] contains the first word (Name) and a[2] contains the second word (Surname).

$ awk -F: '{split($5,a,/[[:blank:]]+/); print a[1],a[2]}' file
Name Surname
Name2 Surname2
Name3 Surname3

Upvotes: 1

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