CODEWITHSUNDEEP
iosstringswiftsubstringtrim
Jacob King
Jacob King

Reputation: 6157

Trim end off of string in swift, getting error at runtime

I'm making a calculator app in Swift, once my answer is obtained I want to display it in a UILabel. Only problem is I want to limit said answer to 8 characters. Here is my code:

let answerString = "\(answer)"
    println(answer)
    calculatorDisplay.text = answerString.substringToIndex(advance(answerString.startIndex, 8))

This does not return any compiler errors but at runtime I get:

fatal error: can not increment endIndex

Any and all help would be greatly appreciated.

Upvotes: 1

Views: 500

Answers (1)

Martin R
Martin R

Reputation: 539805

There are two different advance() functions: 

/// Return the result of advancing `start` by `n` positions. ...
func advance<T : ForwardIndexType>(start: T, n: T.Distance) -> T

/// Return the result of advancing start by `n` positions, or until it
/// equals `end`. ...
func advance<T : ForwardIndexType>(start: T, n: T.Distance, end: T) -> T

Using the second one you can ensure that the result is within the valid bounds of the string:

let truncatedText = answerString.substringToIndex(advance(answerString.startIndex, 8, answerString.endIndex))

Update for Swift 2/Xcode 7:

let truncatedText = answerString.substringToIndex(answerString.startIndex.advancedBy(8, limit: answerString.endIndex))

But a simpler solution is

let truncatedText = String(answerString.characters.prefix(8))

Update for Swift 3/Xcode 8 beta 6: As of Swift 3, "collections move their index", the corresponding code is now

let to = answerString.index(answerString.startIndex,
                            offsetBy: 8,
                            limitedBy: answerString.endIndex)
let truncatedText = answerString.substring(to: to ?? answerString.endIndex)

The simpler solution

let truncatedText = String(answerString.characters.prefix(8))

still works.

Upvotes: 4

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