CODEWITHSUNDEEP
javajavafxjavafx-2bar-chart
manidu
manidu

Reputation: 35

JavaFX - How to sort values in a BarChart

I have the following JavaFX BarChart (NumberAxis on the bottom, CategoryAxis on the left):

https://i.sstatic.net/jpiu1.png

How can I reverse (i.e. sort by value) the order of the categories, so that J shows at the top and A at the bottom?

Upvotes: 0

Views: 2360

Answers (2)

sushmitha shenoy
sushmitha shenoy

Reputation: 349

The chart data could be sorted in the decreasing order of their sizes so that the category axis is always sorted .

bc.getData().sort((Series<String, Number> o1, Series<String, Number> o2) -> o1.getData().size() <= o2.getData().size()?1:0);

Upvotes: 0

In&#225;cio Nery
In&#225;cio Nery

Reputation: 31

You can do this:

XYChart.Series series1 = new XYChart.Series();
series1.getData().add(new XYChart.Data(1, "A"));
series1.getData().add(new XYChart.Data(1, "B"));
series1.getData().add(new XYChart.Data(1, "C"));
series1.getData().add(new XYChart.Data(1, "D"));
series1.getData().add(new XYChart.Data(1, "E"));
series1.getData().add(new XYChart.Data(2, "F"));
series1.getData().add(new XYChart.Data(2, "G"));
series1.getData().add(new XYChart.Data(4, "H"));
series1.getData().add(new XYChart.Data(4, "J"));

Collections.sort(series1.getData(), new Comparator<XYChart.Data>() {

    @Override
    public int compare(Data o1, Data o2) {
        Number xValue1 = (Number) o1.getXValue();
        Number xValue2 = (Number) o2.getXValue();
        return new BigDecimal(xValue1.toString()).compareTo(new BigDecimal(xValue2.toString()));
    }
});

Upvotes: 2

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