Reputation: 543
The pdf of a standard Gamma distribution is $f(x) = \frac{x^{\gamma-1} \exp(-x)}{\Gamma(\gamma)}$
. How do I find the pdf of of the random variable Z = X + Y
where Y
is the Normal distribution? There is no closed form analytical solution, and it is very difficult to start analytically. SO, was wondering if there is a way to use software tools that will compute the pdf using convolution.
Upvotes: 1
Views: 263
Reputation: 13131
How do I find the pdf of of the random variable Z = X + Y where Y is the Normal distribution?
So you must mean X is the Gamma distribution. In Mathematica:
d = TransformedDistribution[x + y,
{Distributed[x, GammaDistribution[alpha, beta]],
Distributed[y, NormalDistribution[mu, std]]}];
PDF[d, x] // Simplify
gives
(1/(Sqrt[Pi]*Gamma[alpha]))*((2^(-2 + alpha/2)*beta^(-1 - alpha)*
std^(-2 + alpha)*
(Sqrt[2]*beta*std*Gamma[alpha/2]*Hypergeometric1F1[alpha/2, 1/2,
(std^2 + beta*(mu - x))^2/(2*beta^2*std^2)] -
2*(std^2 + beta*(mu - x))*Gamma[(1 + alpha)/2]*
Hypergeometric1F1[(1 + alpha)/2, 3/2, (std^2 + beta
*(mu - x))^2/(2*beta^2*std^2)]))/
E^((mu - x)^2/(2*std^2)))
Mean[d]
Variance[d]
Plot for some parameters
Plot[pdf /. {mu -> 0, std -> 1, alpha -> 1, beta -> 2}, {x, -3, 10}]
Plot[pdf /. {mu -> .5, std -> 2, alpha -> 1, beta -> 5}, {x, -6, 20}]
Upvotes: 2