Nitin Pandey
Nitin Pandey

Reputation: 719

PHP : Array Insertions and Display

I have a SQL query which I'm executing through php. The query results are being displayed correctly.

What am I doing wrong here?? Instead of displaying the results I want to store them in an array and display them later in the below while loop.

$arr = array();    
$sql = "SELECT itemName,itemRating from $userName WHERE itemName IN ( SELECT itemName from $user )";
$result = $conn->query($sql);
$i=0;

if($result)
{
                while($row1=mysqli_fetch_row($result))
                {
                        //echo $row1[0]." ".$row1[1]."<br>";
                        arr[$i]=$row1[0]; //Line 40
                        $i++;   
                }
}

$j=0;

while($j < $i)
{
    echo $arr[$j];
    $j++;
}

Error:

Parse error: syntax error, unexpected '=' in /opt/lampp/htdocs/Project/calculateSimilarity.php on line 40

Upvotes: 0

Views: 51

Answers (3)

Rehan Manzoor
Rehan Manzoor

Reputation: 2753

hope it help..

$arr=array();    
    $sql="SELECT itemName,itemRating from $userName WHERE itemName IN ( SELECT itemName from $user )";
        $result=$conn->query($sql);
        $i=0;
        if($result)
        {
                while($row1=mysqli_fetch_row($result))
                {
                        array_push($arr,$row1[$i]); //Line 40
                        $i++;   
                }
        }
        $j=0;
        while($j<$i)
        {
            echo $arr[$j];
            $j++;
        }

Upvotes: 1

Steve C
Steve C

Reputation: 2786

You have forgotten the $ dollar sign in front

change:

arr[$i]=$row1[0]; //Line 40

to:

$arr[$i]=$row1[0]; //Line 40

Upvotes: 1

Vivek Singh
Vivek Singh

Reputation: 2447

 $arr[$i]=$row1[0];

use it like this..

Upvotes: 1

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