Reputation: 37
So I have been converting a VBA code to OpenOffice BASIC and a simple task as getting the number of the first row of the range has been consuming hours of research.
in VBA:
Cells(3,2) or "mr" is a cell with an input of the kind "A5:G7", so first I splitted the string in a array with A5 and G7.
Rangesplit = Split(Cells(3, 2), ":")
FirstRow = Range(Rangesplit(0)).Row
So far in OpenOfficeBasic:
Rangesplit(mr,":")
I have not been able so far to determine the row and I want to know which function allows me to do it.
Upvotes: 0
Views: 499
Reputation: 36
The following functions will probably help you:
Row_int = oCell.getCellAddress.Row
Col_int = oCell.getCell
Upvotes: 1