CODEWITHSUNDEEP
javascriptarraysslice
Miha Šušteršič
Miha Šušteršič

Reputation: 10062

array.slice returns 1 element instead of two

I have an array that includes 2 strings. One in a list of numbers and another is an integer. I want to get the elements from the first string from start to the place of the integer (if the integer is 2, I want the first two numbers in the string). I've written this code, but it only returns the first character in my string. Can anyone explain why? Thanks

var line = "1,2,3,4,5;2";

line = line.split(";");
console.log(line);

var reverse = line[0].slice(0, parseInt(line[1]));
console.log(reverse);

Upvotes: 2

Views: 179

Answers (3)

4EACH
4EACH

Reputation: 2197

Here is code that return what you need:

  var line = "1,2,3,4,5;2";

line = line.split(";");
var reverse = line[0].split(',').slice(0, parseInt(line[1])).join(',');
console.log(reverse);

enter image description here

Upvotes: 1

adricadar
adricadar

Reputation: 10219

You can use replace(',','') to take only numbers from string.

var reverse = line[0].replace(',','').slice(0, parseInt(line[1],10));


var line = "1,2,3,4,5;2";

line = line.split(";");
console.log(line);

var reverse = line[0].replace(',','').slice(0, parseInt(line[1],10));
console.log(reverse);

Upvotes: 0

Satpal
Satpal

Reputation: 133453

You need to use split first element of line array then you can use join.

var reverse = line[0].split(',').slice(0, parseInt(line[1])).join(',');


var line = "1,2,3,4,5;2";

line = line.split(";");
console.log(line);

var reverse = line[0].split(',').slice(0, parseInt(line[1])).join(',');
console.log(reverse);

Upvotes: 0

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