CODEWITHSUNDEEP
c#asp.net-web-apiasp.net-web-api2asp.net-mvc-5.2
Sergino
Sergino

Reputation: 10838

WebApi return custom ServiceResult

I have normal WebApi controller that with methods:

public class ModelController : ApiController
{
    public IEnumerable<Model> Get()
    {
        return service.Get();
    }

    public string Get(int id)
    {
        return service.Get(id);
    }

    public void Post([FromBody]MyViewModel value)
    {
        return service.Save(value);
    }

    public void Put(int id, [FromBody]MyViewModel value)
    {
        return service.Save(value);
    }

    public void Delete(int id)
    {
        return service.Delete(value);
    }
}

I want to wrap return results in to custom object ServiceResult 

public class ServiceResult<T>
{
    public bool IsError{ get; set; }
    public T ObjectModel {get; set}
}

I want to change the return type on all my controller methods to ServiceResult Here is an example:

public ServiceResult Post([FromBody]MyViewModel value)
{
    service.Save(value);
    //getting error here:
    return new ServiceResult() { IsError= true, ObjectModel = value };
}

But getting the error

The 'ObjectContent`1' type failed to serialize the response body for content type 'application/xml; charset=utf-8'.

Type 'Models.View.MyViewModel' with data contract name 'MyViewModel://schemas.datacontract.org/2004/07/MyViewModel' is not expected. Consider using a DataContractResolver or add any types not known statically to the list of known types - for example, by using the KnownTypeAttribute attribute or by adding them to the list of known types passed to DataContractSerializer.

Do you have any idea how can I fix that?

Upvotes: 0

Views: 1615

Answers (1)

Pradip Nadar
Pradip Nadar

Reputation: 282

Your ServiceResult object requires a type argument, Try this

return new ServiceResult<MyViewModel>() { IsError= true, ObjectModel = value };

Upvotes: 0

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