Reputation: 7554
In Django admin site, when listing all the objects for a given model, I know we can customize which columns get displayed for a ModelA via list_display
Say that ModelA has a one-to-many relationship with ModelB. I would like to add another column on the listing page for ModelA, where each entry is a URL pointing to all objects of ModelB having a foreign key relationship on corresponding instance of Model A in that row. How can I achieve this customization with the admin app?
Upvotes: 2
Views: 2329
Reputation: 6767
you should add a method to ModelA's admin class:
def modelb_link(self, inst):
url = u'../modelb/?modela__id__exact=%d' % inst.id
return u'<a href="%s">Models B</a>' % url
modelb_link.allow_tags = True
modelb_link.short_description = u'Models B'
In the url the 'modela__id__exact' part is a filter for list page, where 'modela' is the name of ForeignKey field, in ModelB class, that links to ModelA.
Then use this method in 'list_display' property and you are done. If you encounter any problems, just ask, I'll try to help.
Greetings, Lukasz
Upvotes: 1