CODEWITHSUNDEEP
c++inheritanceoverriding
Abhishek Bhal
Abhishek Bhal

Reputation: 31

Calling overridden child method from base method in c++

Here is the code:

#include <iostream>
class A 
{
public:
  void foo()
  {
    cout<<"this is base foo()"<<endl;
  }

  void callfoo()
  {
    foo();
  }
};

class B: public A
{
public:
  void foo()
  {
    cout<<"this is child foo()"<<endl;
  }
};

int main()
{
  B b;
  b.callfoo(); //Output: "this is base foo()"
  b.foo();     //Output: "this is child foo()"
  return 0;
}

Now when I call b.callfoo(), instead of calling the foo() of child class B, callfoo() calls foo() of base class A. In class B we have overridden foo() with a new implementation, but still callfoo() is calling the base foo() instead of the child foo(). Please help if you have any explanation for this behaviour.

Upvotes: 2

Views: 2025

Answers (1)

Aasmund Eldhuset
Aasmund Eldhuset

Reputation: 37940

In C++, you need to explicitly mark methods as overridable by adding the virtual keyword: virtual void foo().

Upvotes: 3

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