Reputation: 594
I've just started working through C++ Primer Plus and I have hit a little stump.
const int MONTHS = 12;
const int YEARS = 3;
int sales[YEARS][MONTHS] = {0};
const string months[MONTHS] = {"January", "February", "March", "April", "May", "June", "July",
"August", "September", "October", "November", "December"
};
for (int year = 0; year < YEARS; year++)
{
for (int month = 0; month < MONTHS; month++)
{
cout << "Please enter year " << year + 1 << " book sales for the month of " << months[month] << ": \t";
cin >> sales[year][month];
}
}
int yearlyTotal[YEARS][3] = {0};
int absoluteTotal = 0;
cout << "Yearly sales:" << endl;
for (int year = 0; year < YEARS; year++)
{
cout << "Year " << year + 1 << ":";
for (int month = 0; month < MONTHS; month++)
{
absoluteTotal = (yearlyTotal[year][year] += sales[year][month]);
}
cout << yearlyTotal[year][year] << endl;
}
cout << "The total number of books sold over a period of " << YEARS << " years is: " << absoluteTotal << endl;
I wish to display the total of all three years. The rest of the code works fine: input is fine, individual yearly output is fine but I just can't get three years added together for one final total.
Sample data would be entering 1
for every option, to give me three totals of 12
:
year 1: 12
year 2: 12
year 3: 12The total number of books sold over a period of 3 years is: 12
The final 12
should obviously be 36
.
I did have the total working at one point but I didn't have the individual totals working. I messed with it and reversed the situation.
Upvotes: 2
Views: 602
Reputation: 1109
Check the code below. It will work.
int yearlyTotal[YEARS];
int absoluteTotal = 0;
cout << "Yearly sales:" << endl;
for (int year = 0; year < YEARS; year++)
{
yearlyTotal[year] = 0;
cout << "Year " << year + 1 << ":";
for (int month = 0; month < MONTHS; month++)
{
yearlyTotal[year] += sales[year][month];
absoluteTotal += sales[year][month];
}
cout << yearlyTotal[year] << endl;
}
cout << "The total number of books sold over a period of " << YEARS << " years is: " << absoluteTotal << endl;
Upvotes: 0
Reputation: 46913
The problem is where you have your absoluteTotal
increment you're counting the earlier months multiple times (since yearlyTotal
is a counter, it increments each month, so adding it onto absoluteTotal
every time counts month 1 12 times, month 2 11 times, etc).
Instead, you want that loop to look like this:
for (int year = 0; year < YEARS; year++)
{
cout << "Year " << year + 1 << ":";
for (int month = 0; month < MONTHS; month++)
{
(yearlyTotal[year][year] += sales[year][month]);
}
absoluteTotal += yearlyTotal[year][year];
cout << yearlyTotal[year][year] << endl;
}
So that you count each month only once.
EDIT: Good Person's comment about only needing a 1D array is also correct, of course. :)
Upvotes: 0
Reputation: 1443
#include <iostream>
#include <string>
using namespace std;
int main (void)
{
const int MONTHS = 12;
const int YEARS = 3;
int sales[YEARS][MONTHS] = {0};
const string months[MONTHS] = {"January", "February", "March", "April", "May", "June", "July",
"August", "September", "October", "November", "December"
};
for (int year = 0; year < YEARS; year++)
{
for (int month = 0; month < MONTHS; month++)
{
cout << "Please enter year " << year + 1 << " book sales for the month of " << months[month] << ": \t";
cin >> sales[year][month];
}
}
int yearlyTotal[YEARS] = {0};
int absoluteTotal = 0;
cout << "Yearly sales:" << endl;
for (int year = 0; year < YEARS; year++)
{
cout << "Year " << year + 1 << ":";
for (int month = 0; month < MONTHS; month++)
{
yearlyTotal[year] += sales[year][month];
}
absoluteTotal += yearlyTotal[year];
cout << yearlyTotal[year] << endl;
}
cout << "The total number of books sold over a period of " << YEARS << " years is: " << absoluteTotal << endl;
return 0;
}
When it comes to things like this it helps to write them out on paper first.
Upvotes: 1
Reputation: 101
It looks like you're resetting absoluteTotal
each iteration. Do you really want that?
Maybe this would be what you want?:
absoluteTotal += (yearlyTotal[year][year] += sales[year][month]);
Upvotes: 1