CODEWITHSUNDEEP
pythonlistdictionarymean
Vikash Balasubramanian
Vikash Balasubramanian

Reputation: 3233

average list of dictionaries in python

I have a list of dictionary like this

data = [{'Name': 'john', 'Height': 176, 'Weight':62, 'IQ':120,..},...]

the .. signifies various other integer/float attributes and all elements of the list has same format..

I want to get the average Height, Weight and all other numerical attributes in the cleanest/easiest way.

I could not come up with a better way than normal for looping which was too messy... and i don't want to use any external packages

Upvotes: 0

Views: 1168

Answers (3)

Salvatore Avanzo
Salvatore Avanzo

Reputation: 2786

You can use the following

sum([item['Weight'] for item in data])/len(data)

and use 

float(len(data))

if you want a more exact value.

Upvotes: 1

Bhargav Rao
Bhargav Rao

Reputation: 52071

Here is a start for you 

>>> data = [{'Name': 'john', 'Height': 176},{'Name': 'Vikash', 'Height': 170}]
>>> vals = [i['Height'] for i in data]
>>> sum(vals)/len(vals)
173

Likewise you can have a different loop for each attribute or put the loop in a function

>>> def avrg(data,s):
...     vals = [i[s] for i in data]
...     return sum(vals)/len(vals)
... 
>>> data = [{'Name': 'john', 'Height': 176, 'Weight':62, 'IQ':120,},{'Name': 'Vikash', 'Height': 170, 'Weight':68, 'IQ':100}]
>>> 
>>> avrg(data,'Weight')
65

Upvotes: 1

Jeff Sloyer
Jeff Sloyer

Reputation: 4964

Yeah there really isn't a better way than looping. Your basic issue is you have to look at each element in the list, you can't really do that without looping.

Upvotes: 1

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