Reputation: 1209
I have an issue regarding conditional inner join. Kindly have a look at the following sqlfiddle.
http://sqlfiddle.com/#!4/6dc88
Here i'm trying to get all the same name. but if in case the id is 1 then also get the same name and the name which has id of 0. Your help will be appriciated. thanks. here is the example
Table1
Id | Name
1 | A
2 | B
3 | C
Table2
Id | Name
1 | a
2 | b
3 | c
0 | d
Here is what i expect
A | a
B | b
C | c
A | d
Edit: Sorry i forget to mention my query, here is what i have tried so far..
select t1.name, t2.name from table1 t1
inner join table2 t2 on
CASE
WHEN t1.id = t2.id_copy and t1.id = 1 THEN
0
else
t1.id
END = t2.id_copy
Thanks in advance.
Upvotes: 2
Views: 5067
Reputation: 23578
Assuming you mean that if table2.id is 0 then it should match with table1.id = 1, then this should do the trick:
with table1 as (select 1 id, 'A' name from dual union all
select 2 id, 'B' name from dual union all
select 3 id, 'C' name from dual),
table2 as (select 1 id, 'a' name from dual union all
select 2 id, 'b' name from dual union all
select 3 id, 'c' name from dual union all
select 0 id, 'd' name from dual)
select t1.name, t2.name
from table1 t1
inner join table2 t2 on (t1.id = case when t2.id = 0 then 1 else t2.id end);
NAME NAME_1
---- ------
A a
B b
C c
A d
If there's more complicated logic around what decides how non-matching (t1.id = t2.id) rows in table2 match with table1, then you'll have to explain the logic.
Upvotes: 4
Reputation: 1857
Personally I would prefer to use something simpler, like:
select t1.name, t2.name from table1 t1
inner join table2 t2
on t1.id = t2.id_copy or (t1.id = 1 and t2.id_copy = 0)
Upvotes: 3