CODEWITHSUNDEEP
java
Ricky
Ricky

Reputation: 133

Calculate the power of a number in input

I was writing a practice program in Java for one number raised to the other. Unknowingly I made a peculiar mistake which I caught. However the answer still came out correct no matter the input I give. Below is the piece of code.

public static void main(String args[])
{
    int count;
    int num1, num2, result = count =1;
    try(Scanner n1 = new Scanner(System.in))
    {
        System.out.println("Enter the 1st number");
        num1 = n1.nextInt();
        System.out.println("Enter the 2nd number");
        num2 = n1.nextInt();
    }
    while(count<=num2)
    {
        if(num2!=0)
        {
            result = num1*result;
            count++;
        }
        else
        {
            System.out.println(num1+" to the power "+num2+" is "+num1);
        }
    }
    System.out.println(num1+" to the power "+num2+" is "+result);
}

I'm going crazy as to what exactly happened. how come the statement "System.out.println(num1+" to the power "+num2+" is "+num1)" didn't print value of num1.

Following is the output:

 {
 Enter the 1st number
 100
 Enter the 2nd number
 0
 100 to the power 0 is 1
 }

I use ECLIPSE LUNA to code java.

Upvotes: 1

Views: 1279

Answers (1)

Eran
Eran

Reputation: 394026

Well, assuming that you initialize count and result to 1 (which, after your edit, I see was a correct assumption), if num2 is 0, the loop is not entered at all, and all you see is the output printed by the last line (after the loop).

Therefore it doesn't matter what you have inside the loop in this case - System.out.println(num1+" to the power "+num2+" is "+num1); will never be executed when num2 is 0.

Upvotes: 6

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