Reputation: 19
I am getting the json from zoho. I have a JSON like the following:
{
"response": {
"result": {
"Leads": {
"row": [
{
"no": "1",
"FL": [
{
"content": "1325469000000679001",
"val": "LEADID"
},
{
"content": "1325469000000075001",
"val": "SMOWNERID"
},
{
"content": "Geoff",
"val": "Lead Owner"
},
]
},
{
"no": "2",
"FL": [
{
"content": "1325469000000659017",
"val": "LEADID"
},
{
"content": "1325469000000075001",
"val": "SMOWNERID"
},
{
"content": "Geoff",
"val": "Lead Owner"
},
]
},
]
}
},
"uri": "/crm/private/json/Leads/getRecords"
}
}
I am using the following classes:
public class Row
{
[JsonProperty(PropertyName = "row")]
public List<Leads> row { get; set; }
}
public class Leads
{
[JsonProperty(PropertyName = "no")]
public string nbr { get; set; }
[JsonProperty(PropertyName = "FL")]
public List<Lead> FieldValues { get; set; }
}
public class Lead
{
[JsonProperty(PropertyName = "content")]
public string Content { get; set; }
[JsonProperty(PropertyName = "val")]
public string Val { get; set; }
}
I try to deserialize the json and get back nothing:
var mList = JsonConvert.DeserializeObject<IDictionary<string, Row>>(result);
This is the first time working with Json so any help would be appreciated!
Upvotes: 0
Views: 77
Reputation: 18165
Usually when that happens it is because your class model for deserialization is wrong. Rather than trying to hand-craft the classes I like to use http://json2csharp.com. Just plug in your JSON and it gives you the necessary C# classes. In your case it provides the following.
public class FL
{
public string content { get; set; }
public string val { get; set; }
}
public class Row
{
public string no { get; set; }
public List<FL> FL { get; set; }
}
public class Leads
{
public List<Row> row { get; set; }
}
public class Result
{
public Leads Leads { get; set; }
}
public class Response
{
public Result result { get; set; }
public string uri { get; set; }
}
public class RootObject
{
public Response response { get; set; }
}
You can then deserialize into RootObject using:
var mList = JsonConvert.DeserializeObject<RootObject>(result);
Feel free to rename RootObject
to whatever name you like better.
Upvotes: 3