CODEWITHSUNDEEP
phpphpstorm
Md. Yusuf
Md. Yusuf

Reputation: 522

phpstorm doesn't give suggestion

I have two classes A and B and A class has property of B class object. When I try to call this B class function phpstorm does not show any suggestion. I'm doing like this

Class A {
    public $b;
    function __construct($b) {
        $this->b = $b;
    }
    public function  someWork() {
        $this->b->anotherWork();
    }
}

Class B {
    public function callA() {
        $a = new A($this);
        $a->someWork();
    }
    public function anotherWork() {
        echo "do somethings";
    }
}

$b = new B();
$b->callA();

when typing $this->b->anotherWork() phpstorm does not show any suggestion. Is there any way to get suggestion of all class B function from this b variable.

Upvotes: 0

Views: 127

Answers (2)

user1864610
user1864610

Reputation:

Use type hinting.

In class A declare your constructor like this:

public function _construct(B $b) {
  // do stuff
}

This also allows PHP to type check the argument at runtime and report an error if it is wrong.

Upvotes: 1

nateevans
nateevans

Reputation: 426

Try type hinting on the variable and/or PHPDoc on the function and it should work great. 

Class A {
    /** @var B */
    public $b;

    /**
     * @param B $b
     */
    function __construct($b) {
        $this->b = $b;
    }
    public function  someWork() {
        $this->b->anotherWork();
    }
}

Upvotes: 3

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