CODEWITHSUNDEEP
c#json.net
user1429899
user1429899

Reputation: 288

Deserialize JSON property starting with @ symbol into C# dynamic object?

How to deserialize Json property to dynamic object if it starts with @ symbol.

{
    "@size": "13",
    "text": "some text",
    "Id": 483606
}

I can get id and text properties like this. 

dynamic json = JObject.Parse(txt);
string x = json.text;

Upvotes: 10

Views: 7334

Answers (2)

Les
Les

Reputation: 10605

Since you can't use @ in a C# token name, you would need to map the @size to something else, like "SizeString" (since it is a string in your JSON above). I use the WCF data contract attribute, but you could use the equivalent JSON attribute

...
[DataMember(Name = "@size")]
public string SizeString { get; set; }
...

Here is an example of how to deserialize the Json string. Maybe you can adapt to your situation, or clarify your question.

...
string j = @"{
            ""@size"": ""13"",
            ""text"": ""some text"",
            ""Id"": 483606
        }";
        MyClass mc = Newtonsoft.Json.JsonConvert.DeserializeObject<MyClass>(j);
...

[DataContract]
public class MyClass
{
    [DataMember(Name="@size")]
    public string SizeString { get; set; }
    [DataMember()]
    public string text { get; set; }
    [DataMember()]
    public int Id { get; set; }
}

If you don't plan loading the Json into a predefined class, you can do the following...

var o = JObject.Parse(j);
var x = o["text"];
var size = o["@size"];

Upvotes: 17

stefankmitph
stefankmitph

Reputation: 3306

Assuming you use Json.NET:

public class MyObject
{
    [JsonProperty("@size")]
    public string size { get; set; }

    public string text { get; set; }

    public int Id { get; set; }
}

var result = JsonConvert.DeserializeObject<MyObject>(json);

Upvotes: 14

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