Reputation: 2946
simple question regarding HQL(Hibernate query language)
so i have user class , that can hold a list of Projects, how do i take this out of the database depending on a username,
this is how i take out my user
String username = "stephen";
YFUser user = (YFUser) session.createQuery(
"select u FROM YFUser u where u.username = :username")
.setParameter("username", name).uniqueResult();
but i want to take out the list of projects
here is the projects list within the class YFUser(my user class);
how would i query the database to get this list of projects
@Entity
@Table(name = "yf_user_table")
public class YFUser implements Serializable,ILightEntity {
.........
@OneToMany(cascade = CascadeType.ALL,fetch = FetchType.LAZY)
@JoinTable(name = "YFUSER_JOIN_PROJECT", joinColumns = {
@JoinColumn(name = "user_id") }, inverseJoinColumns = {
@JoinColumn(name = "project_id") })
private List<Project> projects = new ArrayList<Project>();
Upvotes: 1
Views: 328
Reputation: 1466
Just made the following change in your code.
List <> user= (YFUser) session.createQuery( "select u FROM YFUser u where u.username = :username") .setParameter("username", name).list();
Upvotes: 0
Reputation: 242786
List<Project> projects = (List<Project>) session.createQuery(
"select u.projects FROM YFUser u where u.username = :username")
.setParameter("username", name).list();
Upvotes: 1