CODEWITHSUNDEEP
pythonpython-3.xinvalidation
onlyme
onlyme

Reputation: 103

Invalid syntax when using "%" sign on print function on python 3.4.3

I'm trying to print stuff on python 3.4.3 on the following way:

a=1    
b=2
print("text text %2d text text %2d", %(a,b))

but when I try to run this simple code it appears a mark exactly over the last "%" sign "invalid syntax":

  File "<stdin>", line 1
    print("text text %2d text text %2d", %(a,b))
                                         ^
SyntaxError: invalid syntax

Upvotes: 0

Views: 1545

Answers (2)

Kasravnd
Kasravnd

Reputation: 107347

You dont need comma after Your string :

print("text text %2d text text %2d" %(a,b))

The % operator can also be used for string formatting. It interprets the left argument much like a sprintf()-style format string to be applied to the right argument, and returns the string resulting from this formatting operation

Also python documentation says :

because this old style of formatting will eventually be removed from the language, str.format() should generally be used.

So you can use str.format:

print("text text {:2d} text text {:2d}".format(a,b))

Upvotes: 2

Martijn Pieters
Martijn Pieters

Reputation: 1124378

You need to remove the comma:

print("text text %2d text text %2d", %(a,b))
#                                  ^

The % is an binary operator, it works on two inputs. Here those inputs are the string and the (a, b) tuple:

print("text text %2d text text %2d" % (a,b))

Upvotes: 1

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