CODEWITHSUNDEEP
bash
King110
King110

Reputation: 122

Bash string to number with number leading with zeros

Can someone explain how the number 2909 is generated in this bash code? and how to fix it without sed/awk/dc.

s="05535"
echo $(( s ))
>> 2909

currently have this is my code which I don't like.

s=$(echo "$s 0 -p" | dc)

Upvotes: 0

Views: 230

Answers (2)

David C. Rankin
David C. Rankin

Reputation: 84642

In addition to the other methods, simple string indexes can provide both the test and the conversion:

[ ${s:0:1} -eq 0 ] && s=${s:1}

If you are concerned about multiple leading 0's, then

 while [ ${s:0:1} -eq 0 ]; do s=${s:1}; done

Upvotes: 0

anubhava
anubhava

Reputation: 786091

2909 is decimal value (base 10) for octal 05535.

Any number starting from 0 is considered an octal value and ((..)) prints decimal value by default.

To keep number it's decimal value use (thanks to @thatotherguy):

s="05535"
echo $(( 10#$s ))
5535

Upvotes: 2

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