CODEWITHSUNDEEP
cakephp
Dvd74
Dvd74

Reputation: 53

Cakephp 2 virtual field not function

I have problem with virtual field, can you help me?

My model UserAddress

public $belongsTo = array(
    'User' => array(
        'className' => 'User',
        'foreignKey' => 'user_id',
        'conditions' => '',
        'fields' => '',
        'order' => ''
    )
);

public $virtualFields = array('users_list' => 'concat(User.name, " - ", User.surname, " - ", User.email)');

My controller UserAddressesController:

$users = $this->User->find('list', array('list',array('fields' => array("id","users_list"))));
$this->set(compact('users'));

My view UserAddresses/edit:

 <?php echo $this->Form->input('users_id', array('class' => 'form-control')); ?>

Report notice:

Notice (8): Undefined variable: users_list [APP/Plugin/User/Controller/UserAddressesController.php, line 94] Code Context
array('fields' => array("id","users_list"))));

Upvotes: 0

Views: 120

Answers (1)

Corie Slate
Corie Slate

Reputation: 616

The resolution from the comment above:

The find call doesn't need the 'list' value in the options array. It should just be $this->User->find('list', array('fields' => array(...

Upvotes: 0

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